There's the one that comes with Python: http://docs.python.org/library/functions.html#round
You should consider working with integers, though. Multiply all the values by 1000 and drop the fractional part. Cheers On Tuesday 09 August 2011, Shwinn Ricci wrote: > When comparing a given value with a database of values, but allowing for > freedom due to variation at say, the thousandth digit, how does one > generalize the precision to this degree? I don't want to truncate, so is > there a round() function that takes into account what decimal place the > value (database value) needs to be rounded to? _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
