64-bit Vista Python 3.2.1 I would like to write a function that would take a path such as 'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf' and return 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' . I've tried this:
def test(path): return path.replace('\', '/') print(test('C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf')) gets me File "c:\P32Working\untitled-5.py", line 2 return path.replace('\', '/') ^ SyntaxError: EOL while scanning string literal Process terminated with an exit code of 1 Thanks, Dick
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