Emeka wrote: > for i,cha in enumerate(wordi): > > label = Label(root, image=photoimage, text = cha) > label.grid(row=1, column=i, columnspan=1, rowspan=1,sticky=W+E+N+S, > padx=0, pady=1) > label1 = Label(root, image=IMAGE) > > I used grid ... Though I used labels, I was dealing only on character > level. > So for word like "JAVA" . I will have a row with four cells and each > filled with the individual character so that I could manipulate them > individually. > > Now, if I late have "ORACLE" in level 2.. I would want to use to write it > in the same row as above however with six cells.
Keep the labels in a list and ensure that there are enough labels (the list is long enough) before you configure them to show the characters. Use the grid_forget() method to hide extra labels if the current word is shorter than a previous one. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
