Is there a less clunky way to do this? [code] def new_pass(): series = ['`', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0', '-', '=', \ '~', '!', '@', '#', '$', '%', '^', '&', '*', '(', ')', '_', '+', \ 'q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p', '[', ']', '\\', \ 'Q', 'W', 'E', 'R', 'T', 'Y', 'U', 'I', 'O', 'P', '{', '}', '|', \ 'a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', ';', "'", \ 'A', 'S', 'D', 'F', 'G', 'H', 'J', 'K', 'L', ':', '"', \ 'z', 'x', 'c', 'v', 'b', 'n', 'm', ',', '.', '/', \ 'Z', 'X', 'C', 'V', 'B', 'N', 'M', '<', '>', '?'] passwd = [] p = input("Enter the length you want your password to be: ") # length of password for i in range(p): r = random.randint(0, 94) passwd.append(series[r]) # Append a random char from series[] to passwd #print passwd #print passwd[0], passwd[1], passwd[2], passwd[3] print "" print "".join(map(str, passwd)), " is your new password. \n" [/code]
[output] >>> Enter 1 to run a MD5 hash on your password Enter 2 to run a SHA1 hash on your password Enter 3 to run a SHA224 hash on your password Enter 9 to get a new randomy password Enter 10 to run away... he he he Enter your choice here> 9 Enter the length you want your password to be: 4 !bnR is your new password. >>> [/output] -- This Apt Has Super Cow Powers - http://sourcefreedom.com
hashy.py
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