I am trying to upload a xml file via pycurl, I really need some help here. 

 

url = "https://192.168.0.68/fileupload/upload_file.php";

 

binaryptr = open('activation.xml','rb').read()

head = ['Content-type:text/xml']

c.setopt(c.SSL_VERIFYPEER, 0)

c.setopt(c.SSL_VERIFYHOST, 0)

c.setopt(c.POSTFIELDS,binaryptr)

c.setopt(c.POSTFIELDSIZE,23L)

c.setopt(c.HTTPHEADER,head)

c.setopt(c.URL, url)

c.setopt(c.VERBOSE, 1)

c.perform() 

 

Regards Rayon

 

_______________________________________________
Tutor maillist  -  Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor

Reply via email to