Is there a way to write an if statement that will pick up duplicates (two ‘1’s):
L = ['1', '4', '1']
if (L[0]) != (L[1]) != (L[2]):
print "THEY ARE NOT EQUAL"
else:
print "THEY ARE EQUAL"
When I run this code, it prints “THEY ARE NOT EQUAL” when it should print the
else “THEY ARE EQUAL”.
list L has two ‘1’s; therefore I am trying to get an if statement that will
recognize this. When using the != (not equal) operator, shouldn’t the if be
true when items in list are not the same? Any input would be appreciated.
Thanks,
Greg
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