"Mateusz Korycinski" <mat.korycin...@gmail.com> wrote
My problem is simple for sure, but unfortunately I'm a bit beginner
and I've
stucked in it. I hope it is not a problem since as I understand this
mailing
list is for beginners.
No problem, we try to answer questions such as this here.
I have some problem with 'for' loop in algorithm.
Code and description for this problem could be find here:
http://stackoverflow.com/questions/5520145/how-to-stop-iteration-when-if-statement-is-true
There are several ways to get out of a loop, the most common are:
a) To exit a single level of loop use break
for n in range(500):
if n == 200: break
else; pass
b) To break out of a set of nested loops such as you have then
use break combined with a sentinal and check the sentinal at
each level:
exitLoop = False
for x in range(20):
if exitLoop : break
for y in range(50):
if exitLoop: break
for z in range(500):
if z == 200:
exitLoop = True
break
c) Use an exception:
class ExitLoopException(Exception): pass
try:
for x in range(20):
for y in range(50):
for z in range(500):
if z == 200:
raise ExitLoopException
except ExitLoopException: pass
There are other ways but those should cover most eventualities.
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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