Ben Hunter wrote:
> Hi,
>
> I'm completing the Python lessons on YouTube that Google posted. At the
> end of section 2 of day 2, there is a task to identify files then put them
> in a zip file in any directory. The code is from the 'solution' folder, so
> it's not something I wrote. I suspect I have a problem with PATHS or
> environment variables. I'm new to programming in something as advanced as
> Python, but I do okay with VBA - so I just feel like there's a setting up
> issue somewhere. I'm on Windows 7, tried running this in Idle and from the
> command line.
The commands module used by zip_to() is an unfortunate choice for a tutorial
because it is supposed to work with unix shells only.
> def zip_to(paths, zipfile):
> """Zip up all of the given files into a new zip file with the given
> name."""
> cmd = 'zip -j ' + zipfile + ' ' + ' '.join(paths)
> print "Command I'm going to do:" + cmd
> (status, output) = commands.getstatusoutput(cmd)
> # If command had a problem (status is non-zero),
> # print its output to stderr and exit.
> if status:
> sys.stderr.write(output)
> sys.exit(1)
You can either try to install Cygwin to run your script unchanged or rewrite
the above function to work with subprocess
import sys
from subprocess import Popen, PIPE
def zip_to(paths, zipfile):
command = ["zip", "-j", zipfile]
command.extend(paths)
process = Popen(command, stdout=PIPE, stderr=PIPE)
stdoutdata, stderrdata = process.communicate()
if process.returncode:
sys.stdout.write(stdoutdata)
sys.stderr.write(stderrdata)
sys.exit(1)
You'll still need a zip.exe on your system.
If you're ambitious, have a look at
http://docs.python.org/library/zipfile.html
a library that allows you to create zipfiles in python without the help of
an external program.
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