On 3/14/2011 1:13 PM Mike Franon said...
Thank you everyone who responded, very fast responses I am impressed.
OK now I see where I went wrong
Well, no, I don't think so. Your first test was:
if i=='test1' or 'test2':
which evaluates as true if _either_ i=='test1' _or_ 'test2'
so, the first test is i=='test1' and the second test if simply 'test2'.
Try the following:
if 'test2': print "non-empty strings evaluate as true"
if not "": print "the not of an empty string evaluates true"
HTH,
Emile
and had to do
if (i == 'test1') or (i=='test2'):
I guess I was thinking if I do
a = ['test1', 'flag', 'monday']
for i in a:
It would check each item in the list one at a time like a loop I was
thinking, so the first time it would test for 'test1', and the second
time it would test for 'flag', did not realize it would test the
entire list all at once.
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