i modified the code to be:
fname = "sampledata.txt"
pattern = "-1"
failed = False
for line in open(fname):
data=line.split()
if len(data)==4:
port, channel, lane, eyvt = data
else:
if int(eyvt) == -1:
failed = True
print "Lane %s failed." % lane
if not failed:
print "All lanes pass."
there is traceback error:
Traceback (most recent call last):
File "C:\Python25\myscript\log\readfile9.py", line 10, in <module>
if int(eyvt) == -1:
ValueError: invalid literal for int() with base 10: 'EyVt'
pls help to advise. don't understand int() with base 10 mean?
thanks
tcl76
> To: tutor@python.org
> From: alan.ga...@btinternet.com
> Date: Sun, 9 Jan 2011 14:14:17 +0000
> Subject: Re: [Tutor] Open a text file, read and print pattern matching
>
>
> "tee chwee liong" <tc...@hotmail.com> wrote
>
> > File "C:/Python25/myscript/log/readfile9.py", line 5, in <module>
> > port, channel, lane, eyvt = line.split()
> > ValueError: need more than 2 values to unpack
>
> So you need to ensure that you unpack when you have the right
> number of fields:
>
> either:
>
> data = line.split()
> if len(data) = 4:
> port, channel, lane, eyvt = data
> else: continue
> # rest of your code here...
>
>
> or more pythonically:
>
> try:
> port, channel, lane, eyvt = line.split()
> # the rest of your code here
> except ValueError: continue
>
> HTH,
>
> --
> Alan Gauld
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
>
>
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