"Francesco Loffredo" <f...@libero.it> wrote
did, Roelof's code would work perfectly, and you could store in a
list
all the subsequent changes of a dictionary without calling them with
different names.
You don;'t need dfifferent names. Provided the name creates a
new object inside the loop you can reuse the same name.
Roeloff's problem was that he only created one object, outside
his loop.
lst = []
for n in range(3):
obj = {}
obj[n] = str(n)
lst.append(obj)
Creats a list of 3 distinct dictionaries but only uses one name - obj.
I understand that if .append() stored a copy of the dict in the
list,
you will end up with lots of copies and a huge amount of memory used
by
your list, but that's exactly what will happen if you make those
copies
yourself. But you wouldn't have to devise a way to generate a new
name
for the dictionary every time you need to update it.
Python uses references throughout, what you are suggesting would
be a change to the normal way that Python uses names.
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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