On 10/2/2010 10:45 AM Steve Willoughby said...
On 02-Oct-10 10:32, Emile van Sebille wrote:
Well, not really -- this is the OPs code. I was responding to Joel's
comment of not seeing the entire post.
File "my_turtle.py", line 19
if (abs(turtle.position()[0]) > turtle.window_height()/2) or
^
SyntaxError: invalid syntax
How does Python know that the next line is the continuation of your if
statement, instead of the beginning of a new line of code?
Because of the paren count -- I didn't actually parse the OPs code and
so I assumed that, but now I'll assume the line break probably resulted
post send.
Continuing-to-assume-ly y'rs,
Emile
Here's the code fragment now paren'd...
import turtle, random
def checkForward(distance):
old_position = turtle.position()
turtle._pen.up()
# no show/hide turtle methods in my turtle module !
turtle.forward(distance)
forward_failed = outOfBounds()
turtle.setx(old_position[0]); turtle.sety(old_position[1])
turtle._pen.down()
# no show/hide turtle methods in my turtle module !
if outOfBounds() == 'false':
turtle.forward(distance)
def stuck():
return forward_failed
def outOfBounds():
if ((abs(turtle.position()[0])>turtle.window_height()/2) or
(abs(turtle.position()[1])> turtle.window_width()/2)):
return "true"
else:
return "false"
def randomMove2(d1, d2, a1, a2):
while 1:
turtle.left(random.uniform(a1,a2))
checkForward(random.uniform(d1,d2))
if outOfBounds() == 'true':
turtle.right(180)
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