I forgot to mention that I didn't write that solveCubicEquation.py script. I paid a pittance to mathtalk-ga at the old Google Answers to not only write it, but to explain it. I recommend these 2 pages to those with a mathematical bent:
<http://answers.google.com/answers/threadview?id=433886> <http://answers.google.com/answers/threadview?id=441538> And here's "my" solveCubicEquation.py script: <http://tutoree7.pastebin.com/7v934g6r> On Thu, Sep 16, 2010 at 02:28, Richard D. Moores <rdmoo...@gmail.com> wrote: > On Thu, Sep 16, 2010 at 00:54, Alan Gauld <alan.ga...@btinternet.com> wrote: >> >> "Richard D. Moores" <rdmoo...@gmail.com> wrote >> >>> Some of the scripts written for 2.6 use libraries not yet available for 3.x. >>> So I want to know not how to modify them, but how to run them at the command >>> line. >> >> Install 2.x. >> This is why we keep recommending that beginners stick with 2.x. >> Its why the 2.x line has not died out and still gets new releases. >> >> Eventually the library owners will port their code but until then >> you need to use the version of python they are written for. >> You cannot mix them reliably. > > I should have stated that I have 2.6, 2.7, and 3.1 installed. The > scripts are in 2 groups. One written in 2.6 (or 2.5), the other in 3.1. Most > run fine in the appropriate version of IDLE, or in Wing when I change > between c:\Python31\pythonw31.exe and c:\Python26\python.exe . But > some 2.6 scripts must be run at the command line. All the 3.1 scripts > do, but not the 2.6's. > > So my problem and question is how to set up a command line that will > run not just the 2.6 scripts that must be run there, but all of them. > > And you know what? In thinking through again what my problem was, I > got the idea to try this, and it worked: > > ================================================== > C:\P26Working\Finished>c:\Python26\python.exe solveCubicEquation.py > Enter real coefficients a,b,c: 3,2,1 > a is 3.0 > b is 2.0 > c is 1.0 > equation is (x**3) + (3.000000*x**2) + (2.000000*x) + (1.000000) = 0 > > roots: [(-2.3247179572447463+0j), > (-0.33764102137762697+0.56227951206230142j), > (-0.33764102137762697-0.56227951206230142j)] > > After ignoring very small root.real and root.imag, > and rounding to 4 significant figures: > > root1 is -2.325 > root2 is -0.3376+0.5623j > root3 is -0.3376-0.5623j > > Press Enter to solve another; n to close: > ============================================== > > So thanks to all for trying to help. Without your tries I wouldn't > have figured it out! > > Dick I forgot to mention that I didn't write that solveCubicEquation.py script. I paid a pittance to mathtalk-ga at the old Google Answers to not only write it, but to explain it. I recommend these 2 pages to those with a mathematical bent: <http://answers.google.com/answers/threadview?id=433886> <http://answers.google.com/answers/threadview?id=441538> And here's "my" solveCubicEquation.py script: <http://tutoree7.pastebin.com/7v934g6r> Dick _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
