Thank you Adam. On Tue, Aug 10, 2010 at 7:03 PM, Adam Bark <adam.jt...@gmail.com> wrote:
> On 11/08/10 02:34, Sudarshana Banerjee wrote: > > Hi: I am trying to teach myself Python, and am stuck at the indentation > with the elif statement. > > This is what I am trying to type (as copied from the textbook): > > x=3 > if x==0: > print "x is 0" > elif x&1 ==1: > print "x is a odd number" > elif x&1==0: -- Line 6 > print "x is a even number" > > If I am combining the if and the print statement, then the elif statement > is in the next line, and all is well with the world. If however, I write the > print as a separate statement, I am getting a syntax error after I press > Enter after keying the first elif statement. > > >>> x=3 > >>> if x==0: > print x > elif x==2: > > > Here you have indented the elif statement but it should be at the same > level as the if: > > >>> x=3 > >>> if x==0: > ... print x > ... elif x==2: > ... print "something else" > ... > >>> > > > SyntaxError: invalid syntax > > Again: > >>> x=3 > >>> if x==2: print x > elif x&1 == 1: print 'x is odd' > >>> elif x&1 ==0: print 'x is even' > SyntaxError: invalid syntax > > > I'm not sure what's going on here but the second elif is being interpreted > separate to the rest of the if statement hence a SyntaxError: > > >>> elif x&1 == 0: print "x is even" > File "<stdin>", line 1 > > elif x&1 == 0: print "x is even" > ^ > SyntaxError: invalid syntax > > This works: > > >>> if x==2: print x > ... elif x&1 == 1: print 'x is odd' > ... elif x&1 ==0: print 'x is even' > ... > x is odd > > > > > If I am pressing two Enters, the code executes; so I have a elif without > a if, and again, a syntax error. What am I not doing right? > > Thank you. > > Sudarshana. > > HTH, > Adam. > > > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > >
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