On Mon, Aug 2, 2010 at 8:00 AM, Evert Rol <evert....@gmail.com> wrote: >> Hello Evert Rol, >> Thank you for the menu help, I have completed it with great >> success... There is 1 more problem I am currently having, and when I fix it >> my program will be completed. If you are interested in helping me with this >> last stretch, I will be greatly appreciative. >> >> If you respond with a yes. I will go ahead and send my code over >> and list the problem I am currently having. > > Jason, it makes more sense to send this to the full tutor list, not just to > me:
Ahhhh ha haha, you hit the wrong 'reply to button'. Stupid newb says what? there are more people who can and will help you. Unless I've missed a response to a previous post of yours where people disrecommended your postings, but that shouldn't happen to quickly. > Although in general, it's better to try and solve the problem yourself, and > ask the tutor list if you're really stuck, either with an error or a concept. > And the 'try and solve yourself' step can take one or more days and a lot of > Googling, but in the end you learn a lot from it. > So, depending on your current problem, see if you want to try yourself first, > or that you feel you need the input from the list. > (Code can be included with the mail if short; use something like > http://python.pastebin.com/ if lengthly code.) > > Good luck, > > Evert > > > > > >> >> -Thank You >> >> On Mon, Aug 2, 2010 at 3:35 AM, Evert Rol <evert....@gmail.com> wrote: >> > My problem is choice 3. Exit, if you select no or put an invalid answer... >> > It will run menu1... but then it runs >> > name = raw_input ("Enter your character name. ") >> > print "Your character name is:", name >> > >> > How can i make it so it prints menu1 like normal... then asks you to enter >> > your selection again? >> > instead of running the above code. >> >> Put it in a loop with the necessary break statements. Something like: >> >> while True: >> print menu1 >> answer = raw_input() >> if ...: >> ... >> break >> elif ...: >> ... >> elif ...: >> answer = raw_input() >> if ...: >> sys.exit() >> raw_input('character name') >> >> Only the first option will break out of the loop to the 'character name' >> question; the other two options will continue to loop, apart from the point >> where you exit() the whole program. >> If you need user input until the correct input has been given, that means >> you'll have to wrap things in a loop (generally a while loop that you break >> out of when you received correct input). >> You could factor out the actual code inside the while loop into a function, >> which can make the structure clearer. >> >> >> Btw, >> >> <snip /> >> >> > characterChoice = input ("Enter your choice. ") >> >> You have input() here, while further down raw_input(). The latter is >> preferred in Python 2.x. I assume this is just a minor mistake. >> >> >> Evert >> >> >> > print >> > >> > if characterChoice == 1: >> > print """ >> > >> > *Place Holder* >> > >> > """ >> > >> > elif characterChoice == 2: >> > print "Currently under construction.\nPlease choose again." >> > print menu1 >> > elif characterChoice == 3: >> > endProgram = raw_input ("Do you want to end program? yes or no ") >> > if endProgram == "yes": >> > sys.exit(0) >> > elif endProgram == "no": >> > print menu1 >> > else: >> > print "\nInvalid Command:\nSelect from the menu again.\n" >> > print menu1 >> > >> > print >> > name = raw_input ("Enter your character name. ") >> > print "Your character name is:", name >> > _______________________________________________ >> > Tutor maillist - tu...@python.org >> > To unsubscribe or change subscription options: >> > http://mail.python.org/mailman/listinfo/tutor >> >> > > _______________________________________________ > Tutor maillist - tu...@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
