On Wed, 23 Jun 2010 06:58:25 am Richard D. Moores wrote:
> Please see my Python 3.1 code pasted at
> <http://python.pastebin.com/T3vm9vKT>.
>
> This does what I want, which is to do one of:
> 1. print all the elements of the list, lst.
> 2. print "Done" when "" is entered.
> 3. print the elements of lst whose indexes are entered.
> (sorry if all this is obvious)
>
> Now, the code works, but isn't there a better way to do what I want?
> I've been away from Python for a while, and have gotten rusty.
Seems reasonable to me. Sometimes the simple things are the best.
The only thing I'd do is pre-process the "all" case:
lst = [100,101,102,103]
indexes = input("'Enter indexes': ").split(",")
if indexes == ["all"]:
indexes = list(range(len(lst))
if indexes == [""]:
print("Done")
else:
indexes = [int(k) for k in indexes]
print(indexes)
for i in indexes:
print(lst[i])
--
Steven D'Aprano
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