Thanks for the info. I already adopted a program from another person
and it works like a charm. As for your question, I had no idea of if I
had duplicate or more as there was some 570 line items. I whittled it
down to 370 line entries. Whew.
Ken
Luke Paireepinart wrote:
On Sat, Mar 20, 2010 at 11:34 AM, Ken G. <beach...@insightbb.com
<mailto:beach...@insightbb.com>> wrote:
What is a method I can use to find duplicated entry within a
sorted numeric file?
I was trying to read a file reading two lines at once but
apparently, I can only read one line at a time. Can the same file
be opened and read two times within a program?
For example, a file has:
1
2
2
3
4
4
5
6
6
The newly revised file should be:
1
2
3
4
5
6
Again, thanking the group for their input,
One-liner:
open("output.txt", "w").write("\n".join(sorted(set([i.strip() for i in
open("input.txt")]))))
Just for fun :)
also, in your algorithm, why are you assuming there are at most 1
extra entries in the case of a duplicate? Why not generalize it for
all duplicates?
-Luke
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
