"James Reynolds" <eire1...@gmail.com> wrote
I understand, but if self.value is any number other then 0, then the
"for"
will append to the square list, in which case square_list will always
have
some len greater than 0 when "value" is greater than 0?
And if value does equal zero?
Actually I'm confused by value because you treat it as both an
integer and a collection in different places?
Is this an occasion which is best suited for a try:, except statement? Or
should it, in general, but checked with "if's". Which is more expensive?
try/except is the Python way :-)
def variance(self, *value_list):
if self.value == 0:
var = 0
else:
average = self.mean(*self.value)
for n in range(len(self.value)):
square = (self.value[n] - average)**2
self.square_list.append(square)
var = sum(self.square_list) / len(self.square_list)
return var
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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