"Sander Sweers" <sander.swe...@gmail.com> wrote
On vr, 2010-02-05 at 20:39 +0000, ALAN GAULD wrote:
return float(x1-y1)/(x2-y2)
Does not work properly in version 2. Example is the 3rd doc test:
float((3-2)/(3-1)) gives 0.0 instead of 0.5.
That's what I did wrong dfirst time round, I had the parens round
the whole, it should only be round the first expression.
Alan G.
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