2009/9/16 Igor Mavrović - ma...@irb <igor.mavro...@irb.hr>: > Hi, > > I know about the use of locale module: > >>>> import locale >>>> locale.setlocale(locale.LC_ALL, "hr_HR.UTF8") >>>> print sorted(words, key=locale.strxfrm) > > but I have specific and complicated data structure (list of lists containing > strings, tuples and dictionaries) due to LDAP search result data. > So I use the 'key' option to get to the neaded attributes, and can't use it > for the locale setting. How can I sort this monster list by attribute values > inside it, and still get the correct sorting order? > > Anyone? Thanks in advance! > _______________________________________________ > Tutor maillist - tu...@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor >
The key argument of sorted() and the like takes a function object, so you could do something like the following: def keyfunc(value): keyVal = value[0] #Or whatever lookups are needed return locale.strxfrm(keyVal) then you can call sorted with: print sorted(words, key=keyfunc) You could also do the same with a lambda: print sorted(words, key=lambda o: locale.strxfrm(o[0])) Hope that helps -- Rich "Roadie Rich" Lovely There are 10 types of people in the world: those who know binary, those who do not, and those who are off by one. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
