On Wed, Jul 29, 2009 at 7:43 AM, Nick Burgess <burgess.n...@gmail.com>wrote:
> And you were looking for 192.168.1.2, do you want it to return nothing? Or > both 192.168.1.1 and 192.168.1.10? Or only 192.168.1.1 as it's the closest > match? > > I would like it to return both, all possible matches. > > The data looks something like this in the CSV's, > > Server foo.bar.org 10.2.2.2 such&such org > Apache farm subnet 10.2.3.0/24 so&so corp. > > the format is random > > The script will be ran from a third party tool so only one argument > can be passed to it which will be an entire IP address. If within the > CSV's there is no 32 bit match there could be a subnet that might > match, thats why I need it to loop over the dots. If there is a 32 > bit and a subnet match both will be returned which is desirable . http://www.velocityreviews.com/forums/t356058-regular-expressions-and-matches.html That will give you the regex for matching any IP addresses. If you use the findall method http://docs.python.org/library/re.html then it will give you a list of IPs (as strings). If you packed each of these IPs into a dictionary you could use this to get the key: for ip in iplist: key = ip[:ip.rfind('.')] # Gets everything but the last bit if mydict.get(key): mydict[key].append(ip) else: mydict[key] = [ip] Then you just have to do something like mydict.get(sys.argv[1][:sys.argv[1].rfind('.')] Which will return None or the list of IPs. Although now that I'm thinking a little more about it, that's probably excessive for your needs - you can just do this: matches = [] ipnet = sys.argv[1][:sys.argv[1].rfind('.')] for ip in iplist: if ip.startswith(ipnet): matches.append(ip) and that should give you a list of all IPs within that same subnet. HTH, Wayne
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