<amr...@iisermohali.ac.in> wrote
I have two text file, having entries as
fileA
38 ALA H = 8.29 N = 120.62 CA = 54.33 HA = 4.04 C = 178.95
8 ALA H = 7.85 N = 123.95 CA = 54.67 HA = C =
fileB
8 ALA helix (helix_alpha, helix1)
21 ALA helix (helix_alpha, helix2)
...
those atoms which doesnot have nay value in fileA. so the reult will be
something like:-
fileC
8 ALA H = 7.85 N = 123.95 CA = 54.67 HA =0.00 C =0.00|8 ALA helix
(helix_alpha, helix1)
There is a similar problem discussed a few days ago on tis list,
try looking over the archive for this week to get some ideas.
I tried to merge these two files using commands like:-
from collections import defaultdict
def merge(sources):
... if __name__ == "__main__":
You should not use this inside a function, nor at the >>> prompt.
This is used to determine wheher a file should be treated as a
module or main program. As it stands the rest of your code will
never be executed since the __name__ at the >>> prompt
is never __main__
Looks like you need to go back to fundamentals for a spell.
... a = open("/home/amrita/alachems/chem100.txt")
... c = open("/home/amrita/secstr/secstr100.txt")
... def source(stream):
... return (line.strip() for line in stream)
... for m in merge([source(x) for x in [a,c]]):
... print "|".join(c.ljust(10) for c in m)
I haven't quite got my head around the logic here but it
looks to me like an overly elaborate solution. You could
simplify the last for loop to just do
for m in merge([source(a),source(c)])
But of course that is a recursive function call to merge() and I
can't see any terminating condition so it should loop forever
(or until it reaches the recursion limit)...
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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