Whoops. That's called assuming what I read is really what I see. A good lesson in reading questions twice.
I remember this from a post some time back and I remember having been intrigued by it. I used Google, and since I tend to keep extensive notes, the solution I found is not uniquely mine, but it does work. http://wasstock.com/?p=12 Robert On Thu, 2009-06-18 at 16:23 +0200, karma wrote: > Hi Robert, > > Thanks for the link. However, I am looking for eliminating consecutive > duplicates rather than all duplicates - my example wasn't clear, > apologies for that. > > x=[1,1,1,3,2,2,2,4,4,2,2] > > [1 ,3 ,2 ,4 ,2 ] > > > 2009/6/18 Robert Berman <berma...@cfl.rr.com>: > > This might help: http://code.activestate.com/recipes/52560/ > > > > Robert > > > > > > On Thu, 2009-06-18 at 15:15 +0200, karma wrote: > >> I was playing around with eliminating duplicates in a list not using > >> groupby. From the two solutions below, which is more "pythonic". > >> Alternative solutions would be welcome. > >> > >> Thanks > >> > >> x=[1,1,1,3,2,2,2,2,4,4] > >> > >> [v for i,v in enumerate(x) if x[i]!=x[i-1] or i==0] > >> > >> [x[i] for i in range(len(x)-1) if i==0 or x[i]!=x[i-1]] > >> > >> output: > >> [1, 3, 2, 4] > >> _______________________________________________ > >> Tutor maillist - Tutor@python.org > >> http://mail.python.org/mailman/listinfo/tutor > > > > _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
