OK. With r before the path of the software, it works perfectly. subprocess.Popen([r"C:\Program Files\Editra\Editra.exe", filename]) I saw that once but I don't remember and cannot find the reason for the use of r.
I'll try not to forget to test with and without r in case a file access doesn't work. Thanks a lot to both of you Sander and Alan for your help. Dominique _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
