On Sun, Apr 12, 2009 at 10:21 AM, Sander Sweers <sander.swe...@gmail.com> wrote:
> 2009/4/10 Kent Johnson <ken...@tds.net>:
>> Or, catch
>> the exception, have the code find out where the error is and display
>> the bad line.
>
> This is what I was looking for. I know how to catch the exception but
> how do I make it display the bad line?
You had:
tsoup = BeautifulSoup(readPage('http://url.sanitized'))
and you got
HTMLParseError: malformed start tag, at line 167, column 73
so try something like this (assuming Python 2.x):
from HTMLParser import HTMLParseError
data = readPage('http://url.sanitized')
try:
tsoup = BeautifulSoup(data)
except HTMLParseError, ex:
lines = data.splitlines()
bad_line = lines[ex.lineno]
print ex
print repr(bad_line) # use repr() so non-printing chars will show
Kent
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