Re: [Tutor] Executing a C Program from RH Linux in Python for Win

[Wayne Watson]

Title: Signature.html

Good. Thanks. Here's my code. ========== # Executing a Linux program under Win XP from subprocess import call myProg = call(["C:\Sandia_Meteors\Various\FuzzyLogic\wolf", "-h"]) ========== But msgs are produced ... Traceback (most recent call last):   File "C:/Sandia_Meteors/Sentinel_Development/Development_Sentuser-Utilities/sentuser/fun-subprocess_Linux.py", line 4, in <module>     myProg = call(["C:\Sandia_Meteors\Various\FuzzyLogic\wolf", "-h"])   File "C:\Python25\lib\subprocess.py", line 444, in call     return Popen(*popenargs, **kwargs).wait()   File "C:\Python25\lib\subprocess.py", line 594, in __init__     errread, errwrite)   File "C:\Python25\lib\subprocess.py", line 816, in _execute_child     startupinfo) WindowsError: [Error 5] Access is denied I looked for the attributes on the file and it shows "A". I'm the admin on my XP Pro, and the file is owned by Admin. wolf is a 1 meg file. Alan Gauld wrote: "Wayne Watson" <sierra_mtnv...@sbcglobal.net> wrote What is meant by "The arguments are the same as for the Popen constructor.", in Convenience Functions? In fact, what is such a function? It means that there is a function which takes the same arguments as the __init__() method of the Popen class. They are convenience functions in that you don't need to create the class to use them you can just call them directly. THe payoff is that you lose some of the flexibility of using the class, but often you don;t need that. class subprocess.Popen(args, bufsize=0, executable=None, stdin=None, stdout=None, stderr=None, preexec_fn=None, close_fds=False .... Why not just class Popen instead of subprocess.Popen? The notation is saying that there is a class defined in the subprocess module called Popen with a constructor that has the listed parameters. It is just a shorthand way of expressing that. In practice you would create an instance with either: import subprocess p = subprocess.Popen(....) OR from subprocess import Popen p = Popen(....) Is there a suggestion here that I need only do: from subprocess import Popen myProg=Popen() myProg.call("wolf", "-h") Even simpler, you only need: from subprocess import call myProg = call(["wolf", "-h"]) You need to put the command as the first entry of a list and each argument as a separate entry HTH, -- Wayne Watson (Watson Adventures, Prop., Nevada City, CA) (121.01 Deg. W, 39.26 Deg. N) GMT-8 hr std. time) “Life is one damn thing after another." -- Mark Twain

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