On Mon, Feb 9, 2009 at 3:35 PM, Kayvan Sarikhani <ksarikh...@gmail.com>wrote:
> Hello Tutors, > <snip> I thought that maybe adding "print random.choice(pool).strip()" > might work but not having any luck with that. Is the output this way, simply > because of the nature of the range, or can anyone point my in the right > direction? Thanks in advance! > It's actually not the range but the print function. Print automatically prints a newline. If you were to create a string of what print does: print 'foo' 'foo\n' However, adding a trailing comma will eliminate that. It will still add a trailing space however. A better option would be like Marc suggests, although you have to do concatenation: mystr += random.choice(pool) You do have some other options though. Create a list and join it with '': In [148]: x = ['a','b','c'] In [149]: ''.join(x) Out[149]: 'abc' Create a list, convert it to tuple, and use string formatting: In [151]: '%s%s%s' % t Out[151]: 'abc' Use sys.stdout.write instead: In [154]: for y in x: .....: sys.stdout.write(y) .....: .....: abc and a host of other options. The simplest is probably the concatenation though ;) HTH, Wayne
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