On Sat, Jan 31, 2009 at 1:44 PM, Jay Jesus Amorin <jay.amo...@gmail.com> wrote: > Thanks bob. > > I want to search any characters in test after https://www.localhost.org/ and > the search will end after it finds another / > > and when i print it will display testmodule.
One way to do this would be to use urlparse.urlparse() to split the URL into parts, then reassemble the bits you want. Alternately, you can use a regular expression to split it up: In [1]: import re In [2]: test = "https://www.localhost.org/testmodule/dev/trunk/admin/sql/mytest.sql"; This re finds everything up to the third / as group 1, everything after the third / as group3: In [10]: match = re.search(r'(http(s)?://[^/]+/)(.*)', test) In [11]: match.group(1) Out[11]: 'https://www.localhost.org/' In [12]: match.group(3) Out[12]: 'testmodule/dev/trunk/admin/sql/mytest.sql' You can now split on / to get the first path element: In [13]: match.group(3).split('/')[0] Out[13]: 'testmodule' Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
