Jervis Whitley wrote:
On Fri, Jan 16, 2009 at 9:15 AM, Kent Johnson <ken...@tds.net
<mailto:ken...@tds.net>> wrote:
On Thu, Jan 15, 2009 at 3:44 PM, Jervis Whitley
<jervi...@gmail.com <mailto:jervi...@gmail.com>> wrote:
> how about this:
> items = [(1,'a'),(1,'b'),(2,'a'),(3,'a'),
> (3,'b'),(4,'a'),(5,'a'),(5,'b'),(5,'c')]
> mydict = dict(items)
> items = [item for item in mydict.iteritems()]
That only coincidentally preserves order; the order of items in a
dictionary is, for practical purposes, unpredictable.
BTW [item for item in mydict.iteritems()] can be written as just
mydict.items().
Kent
I realise that what you have said is true, however
can you show me a case where
> items = dict(items).items()
will not preserve order? Thanks.
On my computer:
>>> dict((('z', 1), ('y', 2))).items()
[('y', 2), ('z', 1)]
--
Bob Gailer
Chapel Hill NC
919-636-4239
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