On Tue, January 13, 2009 15:09, Jon Crump wrote: > All, > > Something I don't understand (so what else is new?) about quoting and > escaping: > >>>> s = """ "some" \"thing\" """ >>>> s > ' "some" "thing" '
Correct. Note that """ ... """ is just a string constant the same as "..." is, with the exception that it can easily span multiple physical lines. What happens between the quotes, though, is the same. This includes the fact that \ is used to escape special characters, so \" is how you can type a literal " character without it being interpreted as the end-of-string delimiter. Of course, since this is a triple-double-quoted string, a plain old " won't be confused as such anyway, so yes, in this particular instance they evaluate to the same character when the string object is created. To avoid this, you could either escape the backslashes, so you'd have: s = """ "some" \\"thing\\" """ (now s == ' "some" \"thing\" ') or, I think better, would be to use raw string constants: s = r""" "some" \"thing\" """ (now s == ' "some" \"thing\" ') (note that if you're looking at the representation of s in your interpreter, it'll actually print as ' "some" \\"thing\\" ', since it's showing you that the \s are literal. The actual string value is as intended, though) _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
