On Sat, Jul 26, 2008 at 03:08:45AM -0400, Kent Johnson wrote:
> On Fri, Jul 25, 2008 at 7:35 PM, Mike Meisner <[EMAIL PROTECTED]> wrote:
> > Do you happen to know if there is an efficient way to initialize a list
> > like this without explicitly writing out each element?
>
> You can make a copy of the inner list each time through the loop:
> IP = []
> temp = [[0, 0, 0],[0, 0, 0],[0, 0, 0]]
> # initialize to zero
> for i in range(20):
> IP.append(list(temp))
How about::
In [26]: IP = [[0, 0, 0] for x in range(5)]
In [27]: IP
Out[27]: [[0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0], [0, 0, 0]]
In [28]: id(IP[0])
Out[28]: 13122016
In [29]: id(IP[1])
Out[29]: 13121152
In [30]: id(IP[2])
Out[30]: 13121800
- Dave
--
Dave Kuhlman
http://www.rexx.com/~dkuhlman
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
