You can always make a subclass of the classes you're thinking aren't being
garbage collected and put a print statement in their __del__ functions to
show you when they are. That will show you if/which objects aren't being
deleted.
Do you have any global variables?
--Michael
On Wed, May 7, 2008 at 3:50 PM, Keith Suda-Cederquist <[EMAIL PROTECTED]>
wrote:
> Hi,
>
> I'm doing some image processing using PIL and SciPy. Individual images are
> 2000x2000 pixels with each pixel being 16 bits, so a single image is around
> 7 MB in size.
>
> I've noticed that while my code is running the amount of memory being used
> (as reported by Windows Task Manager) by Python gradually increases. It
> continues to increase if I re-run the same code again from within iPython
> (everytime I re-run the code the memory used increases by about 300 MB). So
> after re-running the code several times (while debugging and/or developing)
> I will eventually get a memory exception (<type 'exceptions.MemoryError'>).
>
> Does this mean I've somehow created a memory leak? From what I've read,
> in Python 2.X creating a memory leak is a hard thing to do. Perhaps I'm
> just doing a terrible job of coding and am constantly creating new things
> that take up memory???
>
> My basic code structure is below. Anyone has any suggestions on how to
> improve the efficiency of my code or to debug this problem?
>
> Thank you in advance,
> Keith
>
> def function1(filename):
> image1=im2array(filename)
> #im2array is a function I wrote to open a tiff image as a scipy array
> #average the 2000x2000 2d array into a single 2000x1 1d array
> # perform some scaling on the 2000x1 1d array
> #take the FFT of the 2000x1 1d array
> result=[fftpeak, fftmaxamplitude] #output is just two float values
> return result
>
> filenames=['file1.tif','file2.tif',...] #about 40 image filenames in this
> list
>
> results=[]
> for ind in xrange(0,len(filenames):
> results.append(function1(filenames[ind]))
>
>
>
>
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>
--
Michael Langford
Phone: 404-386-0495
Consulting: http://www.RowdyLabs.com
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