Hi there, I am using python to do some scripting. In particular, I am using it to run some jobs which require precision inputs. I do this by having python write an input file, which I then feed to some other program.
The problem I am having is getting python to write number into this input file, keeping 16 digits of precision. I have played around interactively, and see that python default prints 17 digits of precision to the screen, but when I use a replace command to write into the input file, it only prints 12 digits of precision. The relevant snipit of my script is value = float( int(ai) * 6 * math.pi / (int(L)*int(T)) replace = {'VALUE':str(value)} ini_file = open('generic_ini').read() f=open('my_input.xml','w') f.write(ini_file % replace) f.close() where, "ai", "L" and "T" are process dependent numbers defined in my script, and the output "my_input.xml", is just an xml file I later feed to another program, and this is why I replace 'VALUE' with a string. To reiterate, I need str(value) to be written to my file with 16 digits of precision...??? Thanks, Andre _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor