Eric and Eric :-)
Thanks both for the suggestions! I learned from each!
I believe the small function will work for me. Its simple since I don't
have to track each pipe I open with a variable. I had no idea I could do
that nifty if/then for the stdin, that makes it so easy. :-)
Thanks again!
Jay
On 11/1/07, Eric Brunson <[EMAIL PROTECTED]> wrote:
>
> jay wrote:
> > Hello,
> >
> > If I have multiple Popen calls I need to make, how can I turn these
> > into a function?
>
> Since you're only interested in the output of the last command on the
> pipeline, I don't see a reason to keep track of them all. I'd do
> something like this:
>
> def pipeline( *commandlist ):
> last = None
> for command in commandlist:
> last = Popen( command,
> stdin=last.stdout if last else None,
> stdout=PIPE )
>
> return last.communicate()[0]
>
> print pipeline( ("ls", "-la", "/etc"),
> ("grep", "hosts"),
> ("awk", "{print $1}") )
>
> returns:
> lrwxrwxrwx
>
>
>
> Hope that helps,
> e.
>
> > from subprocess import Popen, PIPE
> >
> > p1 = Popen(['ls', '-l', '-a', '/etc'],stdout=PIPE)
> > p2 = Popen(['grep', 'hosts'], stdin=p1.stdout, stdout=PIPE)
> > p3 = Popen(['awk', '{print $1}'], stdin=p2.stdout, stdout=PIPE)
> > output = p3.communicate()[0]
> >
> > p1 = Popen(['ps', '-ef'], stdout=PIPE)
> > p2 = Popen(['grep', '-v', '2348'], stdin=p1.stdout, stdout=PIPE)
> > output = p2.communicate()[0]
> >
> > I would be sending an arbitrary number of PIPES with each function call.
> >
> > I'm a little stumped as to how to handle the variables. If I have an
> > arbitrary number of PIPES, how do I declare my variables (p1, p2, p3,
> > etc...) ahead of time in the function??
> >
> > Thanks for any suggestions!
> >
> > Jay
> > ------------------------------------------------------------------------
> >
> > _______________________________________________
> > Tutor maillist - Tutor@python.org
> > http://mail.python.org/mailman/listinfo/tutor
> >
>
>
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