Christopher Spears wrote: > One of the exercises in Core Python Programming is to > create a regular expression that will match a street > address. Here is one of my attempts. > >>>> street = "1180 Bordeaux Drive" >>>> patt = "\d+ \w+" >>>> import re >>>> m = re.match(patt, street) >>>> if m is not None: m.group() > ... > '1180 Bordeaux' > > Obviously, I can just create a pattern "\d+ \w+ \w+". > However, the pattern would be useless if I had a > street name like 3120 De la Cruz Boulevard. Any > hints? >
Maybe : r'^(\d+)\s+(.*?)(?:\s+)?(\d+.*)?$' street = "1180 Bordeaux Drive 5th floor apt 'A'" then : \1 : '1180' \2 : 'Bordeaux Drive' \3 : "5th floor apt 'A'" or : street = "1180 Bordeaux Drive" then : \1 : '1180' \2 : 'Bordeaux Drive' \3 : "" _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
