I've gone ahead and created a script that does this, however it also 
strips punctuation. I was originally just comparing each character to a 
string containing a single space ' ' but even using s[-1].isspace() I 
lose punctuation marks. Any idea why that's happening?

(Not the OP, I just thought this would be interesting to do)

Bob Nienhuis wrote:
> BTW, GMail brings up some interesting sponsored links when the subject 
> line
> has string.strip in it ( :-0)
>
> On 9/30/07, *Alan Gauld* < [EMAIL PROTECTED] 
> <mailto:[EMAIL PROTECTED]>> wrote:
>
>
>     "wesley chun" < [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>> wrote
>     in message
>     news:[EMAIL PROTECTED]
>     >> > I'm not sure how to proceed.  My biggest stumbling
>     >> > block is how to detect the leading and trailing
>     >> > whitespace.
>     >>
>     >> Use indexing.
>     >> Try using a while loop.
>     >> Or maybe two?
>     >>
>     >> And strings have an isspace method...
>     >
>     > unfortunately, the isspace() string method only returns True if all
>     > chars in the string are whitespace chars and False otherwise, so
>     > that's a bummer.
>
>     But the string can be one character long:
>
>     s = 'fred\n'
>     print s[-1].isspace()      # --> True
>
>     :-)
>
>     Alan G
>
>
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