Hi Max,
A better way to check if a number is odd or even would be to find the
remainder after it is divided by two.
for instance: 4 divided by 2 = 2 with 0 remainder
5 divided by 2 = 2 with 1 remainder
6 divided by 2 = 3 with 0 remainder
7 divided by 2 = 3 with 1 remainder
As well as the floor division operator '/', Python has another operator for
finding the remainder (or 'modulus')
On 9/4/07, max baseman <[EMAIL PROTECTED]> wrote:
>
> hello just a quick check in, it's about the same program i was asking
> about before ive let it sit for a few days now and i reached a number
> to high to convert to a decimal by adding 0.0
> here's the program:
>
> count=1
> numstart=268549802
> number=0
> high=0
> a=0
> while 1==1:
> numstart=numstart+1
> number=numstart
> count=1
> while number !=1:
> if number/2 == (number+0.0)/2:
> number=number/2
> else:
> number=(number*3)+1
> count=count+1
> if count > a:
> a=count
> print numstart,":",count
>
>
> after a few days i got this error:
>
> Traceback (most recent call last):
> File "homework6high.py", line 11, in <module>
> if number/2 == (number+0.0)/2:
> OverflowError: long int too large to convert to float
>
> just wondering if theirs a way to check if a larger number is even or
> odd
>
> thanks
>
> _______________________________________________
> Tutor maillist - Tutor@python.org
> http://mail.python.org/mailman/listinfo/tutor
>
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