More than one way to skin a cat:
import operator sort_key = operator.itemgetter(1) sorted(inventory.items(),key=sort_key)[-1]
('oranges',525)
or...
inventory.items()
[('pears', 217), ('apples', 430), ('oranges', 525), ('bananas', 312)]
count_first = [(count,fruit) for fruit,count in inventory.items()] count_first
[(217, 'pears'), (430, 'apples'), (525, 'oranges'), (312, 'bananas')]
max(count_first)
(525, 'oranges') And then of course you could iterate over the dictionary setting up variables that hold the highest fruit and count found so far. On 6/13/07, Carlos <[EMAIL PROTECTED]> wrote:
Hello, If I have a dictionary like: inventory = {'apples': 430, 'bananas': 312, 'oranges': 525, 'pears': 217} How can I get the item with the largest quantity? I tried: max(inventory) but got: 'pears' What I would like to get is 'oranges', at least in this case. Thanks, Carlos _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
_______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor