Hey Matt, Skirting your question that looks like a modulo issue[1]...
Maybe isleapyear[2] will work for you: import calendar calendar.isleap(2007) -> False calendar.isleap(2008) -> True I hope that helps, Eric. [1] http://docs.python.org/ref/binary.html [2] http://docs.python.org/lib/module-calendar.html Matt Smith wrote: > Hi there, > > I'm trying to write a short function to test whether a year is a leap > year or not. To do this I need to check whether the year divides exactly > by 4, 100 and 400. I can't think of an easy way to test whether there is > a remainder or not. The best I can come up with so far is: > > if (year / 4.0) - (year // 4.0) <> 0: > > This doesn't seem to work, it is always True, is there a problem with > the comparison? The arithmetic seems to be the correct way to isolate > the remainder of the division. > > Can anyone suggest a better way of performing this test or alternately, > how can I get the line above to work. > > Thanks, > > Matt > > > _______________________________________________ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor -- -- _________________________ Eric Walstad 2856 Diamond Street San Francisco, CA 94131 [EMAIL PROTECTED] 415-864-4224 _________________________ _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
