vanam wrote: > ya i am sure about that i am using python editor which has python > intrepreter attached to it i got the same output for both filter and map > def squ(n): > y = n*n > print y > filter(y,range(3))->0 1 4 > map(y,range(3))->0 1 4
You are not printing the result of either the filter or map function here. You have the print statement embedded in squ. In fact you wouldn't print anything but a NameError exception here because you haven't passed filter or map a function, just an identifier which isn't in their scope: >>> def squ(n): ... y = n*n ... print y ... >>> filter(y, range(3)) Traceback (most recent call last): File "<stdin>", line 1, in ? NameError: name 'y' is not defined >>> Also not, the function squ as defined here always returns None, so it is useless as either a filtering or mapping function. Printing a value is not the same as returning a value. -- Sincerely, Chris Calloway http://www.seacoos.org office: 332 Chapman Hall phone: (919) 962-4323 mail: Campus Box #3300, UNC-CH, Chapel Hill, NC 27599 _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
