Luke Paireepinart wrote: > I think a better way to do this is to check if 'Level_%i' is in your > dictionary already. > so the loop becomes > > Lev_List = {} > for Element in Elements: > keystr = 'Level_%i' % Element['Level'] > if not Lev_List.has_key(keystr): > Lev_List[keystr] = [] > Lev_List[keystr].append(Element['Name'])
I am a fan of dict.setdefault() which has this logic built in: Lev_List = {} for Element in Elements: keystr = 'Level_%i' % Element['Level'] Lev_List.setdefault(keystr, []).append(Element['Name']) Also there is no need to create a string for the key, Element['Level'] is a fine key: Lev_List = {} for Element in Elements: Lev_List.setdefault(Element['Level'], []).append(Element['Name']) Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor