Chris Hengge wrote:
> Ok, last problem with this whole shebang...
>
> When I write the file from the zip, if it is in a subfolder, it will
> error..
> The code below will detect if the file in contained inside a directory
> in the zip, but I just want it to write it like it wasn't.
> Another words
>
> Zipfile.zip looks like this
> file.ext
> file2.ext
> folder/
> anotherfile.ext
>
> file.ext extracts fine, file2.ext extracts file.. but it see's the last
> file as folder/anotherfile.ext and it can't write it.. I tried to figure
> out how to use .split to get it working right.. but I'm not having any
> luck.. Thanks.
>
> for afile in zfile.namelist(): # For every file in the zip.
> # If the file ends with a needed extension, extract it.
> if afile.lower().endswith('.cap') \
> or afile.lower().endswith('.hex') \
> or afile.lower().endswith('.fru') \
> or afile.lower().endswith('.cfg'):
> if afile.__contains__("/"):
This should be spelled
if "/" in afile:
__contains__() is the method used by the python runtime to implement
'in', generally you don't call double-underscore methods yourself.
I think you want
afile = afile.rsplit('/', 1)[-1]
that splits afile on the rightmost '/', if any, and keeps the rightmost
piece. You don't need the test for '/' in afile, the split will work
correctly whether the '/' is present or not.
If you are on Windows you should be prepared for paths containing \ as
well as /. You can use re.split() to split on either one.
Kent
> outfile = open(afile, 'w') # Open output buffer for
> writing.
> outfile.write(zfile.read(afile)) # Write the file.
> outfile.close() # Close the output file buffer.
> else:
> outfile = open(afile, 'w') # Open output buffer for
> writing.
> outfile.write(zfile.read(afile)) # Write the file.
> outfile.close() # Close the output file buffer.
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