Right think I've got the idea now. Thanks for all contributions on this. Paul -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Karl "Pflästerer" Sent: 25 April 2006 22:28 To: tutor@python.org Subject: Re: [Tutor] Dictionaries and aggregation On 25 Apr 2006, [EMAIL PROTECTED] wrote: [...] > Here's the list I'm starting with: > >>>> for i in rLst: >>>> print i, type(i) > > server001 alive 17.1% 2 requests/s 14805416 total <type 'str'> > server001 alive 27.2% 7 requests/s 14851125 total <type 'str'> > server002 alive 22.9% 6 requests/s 15173311 total <type 'str'> > server002 alive 42.0% 8 requests/s 15147869 total <type 'str'> > server003 alive 17.9% 4 requests/s 15220280 total <type 'str'> > server003 alive 22.0% 4 requests/s 15260951 total <type 'str'> > server004 alive 18.5% 3 requests/s 15484524 total <type 'str'> > server004 alive 31.6% 9 requests/s 15429303 total <type 'str'> > > I've split each string in the list, extracted what I want and feed it into > an empty dictionary. > >>>> rDict ={} >>>> i = 0 >>>> while i < (len(rLst)): >>>> x, y = rLst[i].split()[0], int(rLst[i].split()[3]) >>>> rDict[x] = y >>>> print x, y, type(x), type(y) >>>> i += 1 [...] > What I'm hoping to be able to do is update the value, rather than replace > it, so that it gives me the total i.e. > server001 9 > server003 10 > server002 14 > server004 20 This is easily done. .>>> rdict = {} .>>> for line in lst: .... ans = line.split() .... rdict[ans[0]] = rdict.get(ans[0], 0) + int(ans[3]) .... .>>> rdict .{'server002': 14, 'server003': 8, 'server001': 9, 'server004': 12} Dictionaries have a get() method, which has an optional second argument, which gets returned if there is no such key in the dictionary. Karl -- Please do *not* send copies of replies to me. I read the list _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
