Hey, I'm a Python newbie, and I'm not even sure I've correctly interpreted the problem, but from what I gather the idea is to take an integer with an arbitrary number of digits and return two [strings/lists/tuples/whatever]: one containing all of the odd digits, and another containing all of the even digits. This should work:
def make_string(words):
string = " "
for x in words:
string = string + x + " "
return string
def even_odd(num):
even = []
odd = []
num_string = str(num)
for x in num_string:
a = int(x)
if a%2 == 0:
even.append(x)
else:
odd.append(x)
odd_string = make_string(odd)
even_string = make_string(even)
return (odd_string, even_string)
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