Greetings:
Unfortunately, my problem description was incomplete. I forgot to
include two important requirements:
1. the length of the input string is arbitrary,
2. the order of the digits must be maintained.
I could not find a way to include these requirements in a single, simple
expression. I decided to make an explicit test for string length, which
simplified matters. I came up with this:
>>>>>>>
>>> def odd_even(x):
... if len(x) % 2 == 1:
... return x[::2], x[1::2]
... else:
... return x[1::2], x[::2]
>>> odd_even('987654321')
('97531', '8642')
>>> odd_even('98765432')
('8642', '9753')
>>>
>>>>>>>
which is an improvement, I think, on my original.
Thanks to those who provided suggestions. This is the most useful list
I've ever found.
Regards,
Barry
[EMAIL PROTECTED]
541-302-1107
________________________
We who cut mere stones must always be envisioning cathedrals.
-Quarry worker's creed
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