Victor Bouffier wrote: > If the second element in each array passed as x is of variable length > (that is, it has a different element count than three, in this case), > the program needs to extend the list instead. Without list > comprehensions, and the added capability to utilize and sized list as a > second element, my code ended up looking like the following: > > temporal = [] > for x in elements: > lst = [x[0], description[x[0]]] > lst.extend(x[1]) > temporal.append([x[1][1], lst]) > temporal.sort() > temporal.reverse() # sort descending > elements = [ x[1] for x in temporal ] > > Is there a way to use list comprehensions to append or extend the array > as needed by the second code listing?
I think you are looking for temporal = [ [x[0], description[x[0]]] + x[1] for x in elements ] but I would make two steps, one for the sort using just [ (x[0], x) for x in elements ] then when you pick the data back out you can format it how you like. Kent PS to John: the original solution is using DSU, aka Schwarzian Transform _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
