John Connors said unto the world upon 22/02/06 07:59 PM:
> G'day,
>
> I think my peanut sized brain is starting to understand how to do this.
Glad you're making progress :-) It's normal it takes a while to learn
to adjust your thinking to a rigid and precise system.
I've made some pretty big changes and explained in comments. There are
a couple of bumps up in level of Python-fu, so ask if it puzzles.
Also, watch for the likely improvements on mine, too :-) (I'm no
expert, either.)
Also, I tend to have longer names than most people do. But I think it
is important for understanding longer programs (even your own) that
the names are well chosen.
<snip>
> import random
>
> def dice():
> return random.randint(1,6)
>
> playagain = 'y'
>
> while playagain == 'y':
>
> die1 = dice()
> die2 = dice()
>
> print '1st dice is ',die1,'\n','2nd dice is ',die2
>
> die3 = dice()
> die4 = dice()
> winnum = die3 + die4
>
> print'combined total for the next 2 dice is ',winnum
>
> if winnum == 6:
> print 'you win'
> else:
> print 'you lose'
>
> playagain = raw_input('play again? (y/n) ')
>
> print 'goodbye'
import random
def die_roll():
return random.randint(1,6)
# The while True / break construct avoids the dummy 'y' value
# in your version.
while True:
# This assigns all the dice at once and makes a tuple from the
# list comprehension. A tuple to make the string formatting happy.
rolls = tuple([die_roll() for x in range(4)])
# uses string formatting, a very powerful tool
print '1st die is %s\n2nd die is %s' %(rolls[:2])
turn_score = sum(rolls[2:])
print 'combined total for the next 2 dice is %s' %turn_score
if turn_score == 6:
print 'you win'
else:
print 'you lose'
playagain = raw_input('play again? (y/n) ')
# .lower() to accommodate 'Y'. You might think about how to
# handle 'yes' and the like.
if playagain.lower() != 'y':
break
print 'goodbye'
HTH,
Brian vdB
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