I'm a wee bit confused. > def envoyer(conn, mysize): > print mysize,' KB sent
This doesn't seem to be true from the code. > data = '1'*1024 > data_end = data[:-5]+'#####' > data = data*(mysize-1) So data is mysize-1 KB, but you printed mysize KB? > begining = time.time() > conn.send(data) > conn.send(data_end) > passed = time.time() - begining it migfht be more useful to print the siuze here and work out what you really sent: print 'sent: ',len(data) + len(data_end), 'bytes' > return passed, size where is size defined? > and receive it like this : > > def recevoir(conn): > data='' > while 1: > tmpdata = conn.recv(8192) > data += tmpdata > if '#####' in data: > print 'END OF DATA' > break > print len(data)/1024, ' KB received' > return passed, int(data[-15:-5])/1024 > > But I don't receive as much data that I sent ... does someone know why ? if you are going by your print statements they will not match. > If I want to send the same data back to the client, do I have to destroy > and recreate the socket ? There is nothing to stop you having two sockets, one in each direction. Alan G _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor