If your symbol are specific it is better to use dictionary.
then if the user give an input you can take character by character and translate into your binary.
This is the code textTobinary:
mydic = {'A' : "01000001", 'B' : "01000010", 'C' : "01000011"}
strinput = 'ABBC'
result = [mydic[x] for x in strinput_process]
print result
strinput = 'ABBC'
result = [mydic[x] for x in strinput_process]
print result
Cheers,
pujo
On 9/24/05, Joseph Quigley <[EMAIL PROTECTED]> wrote:
Hi I'm playing with a Binary to text & text to binary converter. I can't
figure out how to replace the characters (first stage: text to binary).
I thought lists would be the best but I really don't know how to use
them... here's my code:
#! /usr/bin/env python
A = "01000001"
B = "01000010"
C = "01000011"
D = "01000100"
E = "01000101"
F = "01000110"
G = "01000111"
H = "01001000"
I = "01001001"
J = "01001010"
K = "01001011"
L = "01001100"
M = "01001101"
N = "01001110"
O = "01001111"
P = "01010000"
Q = "01010001"
R = "01010010"
S = "01010011"
T = "01010100"
U = "01010101"
V = "01010110"
W = "01010111"
X = "01011000"
Y = "01011001"
Z = "01011010"
# Symbols
exclamationPoint = "0010 0001"
hash = "0010 0011"
dollar = "001 0100"
percent = "0010 0101"
_and = "0010 0110"
parentheses = "0010 1000"
closeParentheses = "0010 1001"
comma = "0010 1100"
dash = "0010 1101"
period = "0010 1110"
underline = "0101 1111"
# Numbers
zero = "00110000"
>two = "00110010"
three = "00110011"
four = "00110100"
five = "00110101"
six = "00110110"
seven = "00110111"
eight = "00111000"
nine = "00111001"
ltra = "a"
ltrb = "b"
ltrc = "c"
while True:
text = raw_input("Enter text: ")
text = list(text)
Thanks,
Joe
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