Christopher Arndt wrote: >Hi, > >I wonder if there is a shorter form of the following idiom: > >list1 = [] >list2 = [] >for item in original_list: > if condition(item): > list1.append(item) > else: > list2.append(item) > >(optional step:) > >original_list[:] = list1 > > >I call this the "Aschenputtel" problem, because it is described by the famous >quote from the fairy tale as told by the Grimm brothers: > >"Die guten ins Töpfchen, die schlechten ins Kröpfchen." > >(The good ones in the pot, the bad ones in the crop) > >Chris > > > > >------------------------------------------------------------------------ > >_______________________________________________ >Tutor maillist - Tutor@python.org >http://mail.python.org/mailman/listinfo/tutor > > Well, you there is a way to do it in one line, by having a list of list comprehensions:
>>> olist = range(10) >>> list1, list2 = [[x for x in olist if not x % 2], [i for i in olist if i % 2]] >>> >>> list1 [0, 2, 4, 6, 8] >>> list2 [1, 3, 5, 7, 9] -- Email: singingxduck AT gmail DOT com AIM: singingxduck Programming Python for the fun of it. _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
